5[5-(4-x)]+3x=2(4x+3)-1

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Solution for 5[5-(4-x)]+3x=2(4x+3)-1 equation:


Simplifying
5[5 + -1(4 + -1x)] + 3x = 2(4x + 3) + -1
5[5 + (4 * -1 + -1x * -1)] + 3x = 2(4x + 3) + -1
5[5 + (-4 + 1x)] + 3x = 2(4x + 3) + -1

Combine like terms: 5 + -4 = 1
5[1 + 1x] + 3x = 2(4x + 3) + -1
[1 * 5 + 1x * 5] + 3x = 2(4x + 3) + -1
[5 + 5x] + 3x = 2(4x + 3) + -1

Combine like terms: 5x + 3x = 8x
5 + 8x = 2(4x + 3) + -1

Reorder the terms:
5 + 8x = 2(3 + 4x) + -1
5 + 8x = (3 * 2 + 4x * 2) + -1
5 + 8x = (6 + 8x) + -1

Reorder the terms:
5 + 8x = 6 + -1 + 8x

Combine like terms: 6 + -1 = 5
5 + 8x = 5 + 8x

Add '-5' to each side of the equation.
5 + -5 + 8x = 5 + -5 + 8x

Combine like terms: 5 + -5 = 0
0 + 8x = 5 + -5 + 8x
8x = 5 + -5 + 8x

Combine like terms: 5 + -5 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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